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1.5x^2+3x=498.5
We move all terms to the left:
1.5x^2+3x-(498.5)=0
We add all the numbers together, and all the variables
1.5x^2+3x-498.5=0
a = 1.5; b = 3; c = -498.5;
Δ = b2-4ac
Δ = 32-4·1.5·(-498.5)
Δ = 3000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3000}=\sqrt{100*30}=\sqrt{100}*\sqrt{30}=10\sqrt{30}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-10\sqrt{30}}{2*1.5}=\frac{-3-10\sqrt{30}}{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+10\sqrt{30}}{2*1.5}=\frac{-3+10\sqrt{30}}{3} $
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